Factorial Trailing Digits 2

Problem Statement

For any $N$, let $f(N)$ be the last twelve hexadecimal digits before the trailing zeroes in $N!$.

For example, the hexadecimal representation of $20!$ is 21C3677C82B40000,
so $f(20)$ is the digit sequence 21C3677C82B4.

Find $f(1000 \times 8^N)$. Give your answer as twelve hexadecimal digits, using uppercase for the digits A to F.

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mmtg
$g(5)$, $12$ digits 4 days, 15 hours ago
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mmtg
$g(4)$, $12$ digits 4 days, 15 hours ago
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mmtg
$g(4)$, $12$ digits 4 days, 15 hours ago
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mmtg
$g(3)$, $12$ digits 4 days, 16 hours ago
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mmtg
$g(2)$, $12$ digits 4 days, 16 hours ago